PSLE The perimeter of figure HJKLM is (9
z + 11) cm. The perimeter of square HJKL is 20 cm.
- Find the perimeter of triangle HLM in terms of z.
- The perimeter of figure HJKLM is 65 cm. What is the value of z? Give your answer in cm.
(a)
Length of the square
= 20 ÷ 4
= 5 cm
Total lengths of HJ, JK and KL
= 3 x 5
= 15 cm
Perimeter of triangle HLM
= 9
z + 11 - 5 - 5
= (9
z + 1) cm
(b)
9
z + 11 = 65
9
z = 65 - 11
9
z = 54
z = 54 ÷ 9 = 6
Value of
z = 6 cm
Answer(s): (a) (9
z + 1) cm; (b) 6 cm