PSLE The perimeter of figure JKLMN is (9
t + 18) cm. The perimeter of square JKLM is 16 cm.
- Find the perimeter of triangle JMN in terms of t.
- The perimeter of figure JKLMN is 81 cm. What is the value of t? Give your answer in cm.
(a)
Length of the square
= 16 ÷ 4
= 4 cm
Total lengths of JK, KL and LM
= 3 x 4
= 12 cm
Perimeter of triangle JMN
= 9
t + 18 - 4 - 4
= (9
t + 10) cm
(b)
9
t + 18 = 81
9
t = 81 - 18
9
t = 63
t = 63 ÷ 9 = 7
Value of
t = 7 cm
Answer(s): (a) (9
t + 10) cm; (b) 7 cm