PSLE The perimeter of figure RSTUV is (4
j + 15) cm. The perimeter of square RSTU is 8 cm.
- Find the perimeter of triangle RUV in terms of j.
- The perimeter of figure RSTUV is 31 cm. What is the value of j? Give your answer in cm.
(a)
Length of the square
= 8 ÷ 4
= 2 cm
Total lengths of RS, ST and TU
= 3 x 2
= 6 cm
Perimeter of triangle RUV
= 4
j + 15 - 2 - 2
= (4
j + 11) cm
(b)
4
j + 15 = 31
4
j = 31 - 15
4
j = 16
j = 16 ÷ 4 = 4
Value of
j = 4 cm
Answer(s): (a) (4
j + 11) cm; (b) 4 cm