PSLE The perimeter of figure EFGHJ is (10
c + 18) cm. The perimeter of square EFGH is 12 cm.
- Find the perimeter of triangle EHJ in terms of c.
- The perimeter of figure EFGHJ is 98 cm. What is the value of c? Give your answer in cm.
(a)
Length of the square
= 12 ÷ 4
= 3 cm
Total lengths of EF, FG and GH
= 3 x 3
= 9 cm
Perimeter of triangle EHJ
= 10
c + 18 - 3 - 3
= (10
c + 12) cm
(b)
10
c + 18 = 98
10
c = 98 - 18
10
c = 80
c = 80 ÷ 10 = 8
Value of
c = 8 cm
Answer(s): (a) (10
c + 12) cm; (b) 8 cm