PSLE The perimeter of figure DEFGH is (6
b + 10) cm. The perimeter of square DEFG is 8 cm.
- Find the perimeter of triangle DGH in terms of b.
- The perimeter of figure DEFGH is 58 cm. What is the value of b? Give your answer in cm.
(a)
Length of the square
= 8 ÷ 4
= 2 cm
Total lengths of DE, EF and FG
= 3 x 2
= 6 cm
Perimeter of triangle DGH
= 6
b + 10 - 2 - 2
= (6
b + 6) cm
(b)
6
b + 10 = 58
6
b = 58 - 10
6
b = 48
b = 48 ÷ 6 = 8
Value of
b = 8 cm
Answer(s): (a) (6
b + 6) cm; (b) 8 cm