PSLE The perimeter of figure TUVWX is (6
d + 17) cm. The perimeter of square TUVW is 8 cm.
- Find the perimeter of triangle TWX in terms of d.
- The perimeter of figure TUVWX is 41 cm. What is the value of d? Give your answer in cm.
(a)
Length of the square
= 8 ÷ 4
= 2 cm
Total lengths of TU, UV and VW
= 3 x 2
= 6 cm
Perimeter of triangle TWX
= 6
d + 17 - 2 - 2
= (6
d + 13) cm
(b)
6
d + 17 = 41
6
d = 41 - 17
6
d = 24
d = 24 ÷ 6 = 4
Value of
d = 4 cm
Answer(s): (a) (6
d + 13) cm; (b) 4 cm