PSLE The perimeter of figure TUVWX is (8
a + 19) cm. The perimeter of square TUVW is 16 cm.
- Find the perimeter of triangle TWX in terms of a.
- The perimeter of figure TUVWX is 59 cm. What is the value of a? Give your answer in cm.
(a)
Length of the square
= 16 ÷ 4
= 4 cm
Total lengths of TU, UV and VW
= 3 x 4
= 12 cm
Perimeter of triangle TWX
= 8
a + 19 - 4 - 4
= (8
a + 11) cm
(b)
8
a + 19 = 59
8
a = 59 - 19
8
a = 40
a = 40 ÷ 8 = 5
Value of
a = 5 cm
Answer(s): (a) (8
a + 11) cm; (b) 5 cm