PSLE The perimeter of figure EFGHJ is (9
z + 17) cm. The perimeter of square EFGH is 16 cm.
- Find the perimeter of triangle EHJ in terms of z.
- The perimeter of figure EFGHJ is 80 cm. What is the value of z? Give your answer in cm.
(a)
Length of the square
= 16 ÷ 4
= 4 cm
Total lengths of EF, FG and GH
= 3 x 4
= 12 cm
Perimeter of triangle EHJ
= 9
z + 17 - 4 - 4
= (9
z + 9) cm
(b)
9
z + 17 = 80
9
z = 80 - 17
9
z = 63
z = 63 ÷ 9 = 7
Value of
z = 7 cm
Answer(s): (a) (9
z + 9) cm; (b) 7 cm