PSLE The perimeter of figure JKLMN is (8
v + 22) cm. The perimeter of square JKLM is 24 cm.
- Find the perimeter of triangle JMN in terms of v.
- The perimeter of figure JKLMN is 78 cm. What is the value of v? Give your answer in cm.
(a)
Length of the square
= 24 ÷ 4
= 6 cm
Total lengths of JK, KL and LM
= 3 x 6
= 18 cm
Perimeter of triangle JMN
= 8
v + 22 - 6 - 6
= (8
v + 10) cm
(b)
8
v + 22 = 78
8
v = 78 - 22
8
v = 56
v = 56 ÷ 8 = 7
Value of
v = 7 cm
Answer(s): (a) (8
v + 10) cm; (b) 7 cm