PSLE The perimeter of figure ABCDE is (5
s + 24) cm. The perimeter of square ABCD is 16 cm.
- Find the perimeter of triangle ADE in terms of s.
- The perimeter of figure ABCDE is 64 cm. What is the value of s? Give your answer in cm.
(a)
Length of the square
= 16 ÷ 4
= 4 cm
Total lengths of AB, BC and CD
= 3 x 4
= 12 cm
Perimeter of triangle ADE
= 5
s + 24 - 4 - 4
= (5
s + 16) cm
(b)
5
s + 24 = 64
5
s = 64 - 24
5
s = 40
s = 40 ÷ 5 = 8
Value of
s = 8 cm
Answer(s): (a) (5
s + 16) cm; (b) 8 cm