PSLE The perimeter of figure EFGHJ is (10
i + 13) cm. The perimeter of square EFGH is 8 cm.
- Find the perimeter of triangle EHJ in terms of i.
- The perimeter of figure EFGHJ is 53 cm. What is the value of i? Give your answer in cm.
(a)
Length of the square
= 8 ÷ 4
= 2 cm
Total lengths of EF, FG and GH
= 3 x 2
= 6 cm
Perimeter of triangle EHJ
= 10
i + 13 - 2 - 2
= (10
i + 9) cm
(b)
10
i + 13 = 53
10
i = 53 - 13
10
i = 40
i = 40 ÷ 10 = 4
Value of
i = 4 cm
Answer(s): (a) (10
i + 9) cm; (b) 4 cm