PSLE The perimeter of figure HJKLM is (9
y + 20) cm. The perimeter of square HJKL is 28 cm.
- Find the perimeter of triangle HLM in terms of y.
- The perimeter of figure HJKLM is 101 cm. What is the value of y? Give your answer in cm.
(a)
Length of the square
= 28 ÷ 4
= 7 cm
Total lengths of HJ, JK and KL
= 3 x 7
= 21 cm
Perimeter of triangle HLM
= 9
y + 20 - 7 - 7
= (9
y + 6) cm
(b)
9
y + 20 = 101
9
y = 101 - 20
9
y = 81
y = 81 ÷ 9 = 9
Value of
y = 9 cm
Answer(s): (a) (9
y + 6) cm; (b) 9 cm