PSLE The perimeter of figure DEFGH is (8
r + 24) cm. The perimeter of square DEFG is 8 cm.
- Find the perimeter of triangle DGH in terms of r.
- The perimeter of figure DEFGH is 96 cm. What is the value of r? Give your answer in cm.
(a)
Length of the square
= 8 ÷ 4
= 2 cm
Total lengths of DE, EF and FG
= 3 x 2
= 6 cm
Perimeter of triangle DGH
= 8
r + 24 - 2 - 2
= (8
r + 20) cm
(b)
8
r + 24 = 96
8
r = 96 - 24
8
r = 72
r = 72 ÷ 8 = 9
Value of
r = 9 cm
Answer(s): (a) (8
r + 20) cm; (b) 9 cm