PSLE The perimeter of figure EFGHJ is (4
s + 19) cm. The perimeter of square EFGH is 28 cm.
- Find the perimeter of triangle EHJ in terms of s.
- The perimeter of figure EFGHJ is 51 cm. What is the value of s? Give your answer in cm.
(a)
Length of the square
= 28 ÷ 4
= 7 cm
Total lengths of EF, FG and GH
= 3 x 7
= 21 cm
Perimeter of triangle EHJ
= 4
s + 19 - 7 - 7
= (4
s + 5) cm
(b)
4
s + 19 = 51
4
s = 51 - 19
4
s = 32
s = 32 ÷ 4 = 8
Value of
s = 8 cm
Answer(s): (a) (4
s + 5) cm; (b) 8 cm