PSLE The perimeter of figure EFGHJ is (6
f + 12) cm. The perimeter of square EFGH is 8 cm.
- Find the perimeter of triangle EHJ in terms of f.
- The perimeter of figure EFGHJ is 36 cm. What is the value of f? Give your answer in cm.
(a)
Length of the square
= 8 ÷ 4
= 2 cm
Total lengths of EF, FG and GH
= 3 x 2
= 6 cm
Perimeter of triangle EHJ
= 6
f + 12 - 2 - 2
= (6
f + 8) cm
(b)
6
f + 12 = 36
6
f = 36 - 12
6
f = 24
f = 24 ÷ 6 = 4
Value of
f = 4 cm
Answer(s): (a) (6
f + 8) cm; (b) 4 cm