PSLE The perimeter of figure HJKLM is (5
d + 18) cm. The perimeter of square HJKL is 8 cm.
- Find the perimeter of triangle HLM in terms of d.
- The perimeter of figure HJKLM is 48 cm. What is the value of d? Give your answer in cm.
(a)
Length of the square
= 8 ÷ 4
= 2 cm
Total lengths of HJ, JK and KL
= 3 x 2
= 6 cm
Perimeter of triangle HLM
= 5
d + 18 - 2 - 2
= (5
d + 14) cm
(b)
5
d + 18 = 48
5
d = 48 - 18
5
d = 30
d = 30 ÷ 5 = 6
Value of
d = 6 cm
Answer(s): (a) (5
d + 14) cm; (b) 6 cm