PSLE The perimeter of figure EFGHJ is (9
b + 10) cm. The perimeter of square EFGH is 16 cm.
- Find the perimeter of triangle EHJ in terms of b.
- The perimeter of figure EFGHJ is 91 cm. What is the value of b? Give your answer in cm.
(a)
Length of the square
= 16 ÷ 4
= 4 cm
Total lengths of EF, FG and GH
= 3 x 4
= 12 cm
Perimeter of triangle EHJ
= 9
b + 10 - 4 - 4
= (9
b + 2) cm
(b)
9
b + 10 = 91
9
b = 91 - 10
9
b = 81
b = 81 ÷ 9 = 9
Value of
b = 9 cm
Answer(s): (a) (9
b + 2) cm; (b) 9 cm