PSLE The perimeter of figure HJKLM is (8
m + 15) cm. The perimeter of square HJKL is 8 cm.
- Find the perimeter of triangle HLM in terms of m.
- The perimeter of figure HJKLM is 47 cm. What is the value of m? Give your answer in cm.
(a)
Length of the square
= 8 ÷ 4
= 2 cm
Total lengths of HJ, JK and KL
= 3 x 2
= 6 cm
Perimeter of triangle HLM
= 8
m + 15 - 2 - 2
= (8
m + 11) cm
(b)
8
m + 15 = 47
8
m = 47 - 15
8
m = 32
m = 32 ÷ 8 = 4
Value of
m = 4 cm
Answer(s): (a) (8
m + 11) cm; (b) 4 cm