PSLE The perimeter of figure EFGHJ is (8
v + 18) cm. The perimeter of square EFGH is 8 cm.
- Find the perimeter of triangle EHJ in terms of v.
- The perimeter of figure EFGHJ is 42 cm. What is the value of v? Give your answer in cm.
(a)
Length of the square
= 8 ÷ 4
= 2 cm
Total lengths of EF, FG and GH
= 3 x 2
= 6 cm
Perimeter of triangle EHJ
= 8
v + 18 - 2 - 2
= (8
v + 14) cm
(b)
8
v + 18 = 42
8
v = 42 - 18
8
v = 24
v = 24 ÷ 8 = 3
Value of
v = 3 cm
Answer(s): (a) (8
v + 14) cm; (b) 3 cm