PSLE The perimeter of figure JKLMN is (10
t + 15) cm. The perimeter of square JKLM is 24 cm.
- Find the perimeter of triangle JMN in terms of t.
- The perimeter of figure JKLMN is 95 cm. What is the value of t? Give your answer in cm.
(a)
Length of the square
= 24 ÷ 4
= 6 cm
Total lengths of JK, KL and LM
= 3 x 6
= 18 cm
Perimeter of triangle JMN
= 10
t + 15 - 6 - 6
= (10
t + 3) cm
(b)
10
t + 15 = 95
10
t = 95 - 15
10
t = 80
t = 80 ÷ 10 = 8
Value of
t = 8 cm
Answer(s): (a) (10
t + 3) cm; (b) 8 cm