PSLE The perimeter of figure DEFGH is (9
j + 17) cm. The perimeter of square DEFG is 8 cm.
- Find the perimeter of triangle DGH in terms of j.
- The perimeter of figure DEFGH is 53 cm. What is the value of j? Give your answer in cm.
(a)
Length of the square
= 8 ÷ 4
= 2 cm
Total lengths of DE, EF and FG
= 3 x 2
= 6 cm
Perimeter of triangle DGH
= 9
j + 17 - 2 - 2
= (9
j + 13) cm
(b)
9
j + 17 = 53
9
j = 53 - 17
9
j = 36
j = 36 ÷ 9 = 4
Value of
j = 4 cm
Answer(s): (a) (9
j + 13) cm; (b) 4 cm