PSLE The perimeter of figure TUVWX is (8
r + 15) cm. The perimeter of square TUVW is 8 cm.
- Find the perimeter of triangle TWX in terms of r.
- The perimeter of figure TUVWX is 63 cm. What is the value of r? Give your answer in cm.
(a)
Length of the square
= 8 ÷ 4
= 2 cm
Total lengths of TU, UV and VW
= 3 x 2
= 6 cm
Perimeter of triangle TWX
= 8
r + 15 - 2 - 2
= (8
r + 11) cm
(b)
8
r + 15 = 63
8
r = 63 - 15
8
r = 48
r = 48 ÷ 8 = 6
Value of
r = 6 cm
Answer(s): (a) (8
r + 11) cm; (b) 6 cm