PSLE The perimeter of figure DEFGH is (8
i + 22) cm. The perimeter of square DEFG is 8 cm.
- Find the perimeter of triangle DGH in terms of i.
- The perimeter of figure DEFGH is 94 cm. What is the value of i? Give your answer in cm.
(a)
Length of the square
= 8 ÷ 4
= 2 cm
Total lengths of DE, EF and FG
= 3 x 2
= 6 cm
Perimeter of triangle DGH
= 8
i + 22 - 2 - 2
= (8
i + 18) cm
(b)
8
i + 22 = 94
8
i = 94 - 22
8
i = 72
i = 72 ÷ 8 = 9
Value of
i = 9 cm
Answer(s): (a) (8
i + 18) cm; (b) 9 cm