PSLE The perimeter of figure EFGHJ is (6
s + 17) cm. The perimeter of square EFGH is 12 cm.
- Find the perimeter of triangle EHJ in terms of s.
- The perimeter of figure EFGHJ is 53 cm. What is the value of s? Give your answer in cm.
(a)
Length of the square
= 12 ÷ 4
= 3 cm
Total lengths of EF, FG and GH
= 3 x 3
= 9 cm
Perimeter of triangle EHJ
= 6
s + 17 - 3 - 3
= (6
s + 11) cm
(b)
6
s + 17 = 53
6
s = 53 - 17
6
s = 36
s = 36 ÷ 6 = 6
Value of
s = 6 cm
Answer(s): (a) (6
s + 11) cm; (b) 6 cm