PSLE The perimeter of figure HJKLM is (8
j + 15) cm. The perimeter of square HJKL is 16 cm.
- Find the perimeter of triangle HLM in terms of j.
- The perimeter of figure HJKLM is 79 cm. What is the value of j? Give your answer in cm.
(a)
Length of the square
= 16 ÷ 4
= 4 cm
Total lengths of HJ, JK and KL
= 3 x 4
= 12 cm
Perimeter of triangle HLM
= 8
j + 15 - 4 - 4
= (8
j + 7) cm
(b)
8
j + 15 = 79
8
j = 79 - 15
8
j = 64
j = 64 ÷ 8 = 8
Value of
j = 8 cm
Answer(s): (a) (8
j + 7) cm; (b) 8 cm