PSLE The perimeter of figure HJKLM is (7
e + 16) cm. The perimeter of square HJKL is 8 cm.
- Find the perimeter of triangle HLM in terms of e.
- The perimeter of figure HJKLM is 51 cm. What is the value of e? Give your answer in cm.
(a)
Length of the square
= 8 ÷ 4
= 2 cm
Total lengths of HJ, JK and KL
= 3 x 2
= 6 cm
Perimeter of triangle HLM
= 7
e + 16 - 2 - 2
= (7
e + 12) cm
(b)
7
e + 16 = 51
7
e = 51 - 16
7
e = 35
e = 35 ÷ 7 = 5
Value of
e = 5 cm
Answer(s): (a) (7
e + 12) cm; (b) 5 cm