PSLE The perimeter of figure TUVWX is (9
r + 24) cm. The perimeter of square TUVW is 16 cm.
- Find the perimeter of triangle TWX in terms of r.
- The perimeter of figure TUVWX is 105 cm. What is the value of r? Give your answer in cm.
(a)
Length of the square
= 16 ÷ 4
= 4 cm
Total lengths of TU, UV and VW
= 3 x 4
= 12 cm
Perimeter of triangle TWX
= 9
r + 24 - 4 - 4
= (9
r + 16) cm
(b)
9
r + 24 = 105
9
r = 105 - 24
9
r = 81
r = 81 ÷ 9 = 9
Value of
r = 9 cm
Answer(s): (a) (9
r + 16) cm; (b) 9 cm