PSLE The perimeter of figure HJKLM is (7
p + 12) cm. The perimeter of square HJKL is 12 cm.
- Find the perimeter of triangle HLM in terms of p.
- The perimeter of figure HJKLM is 68 cm. What is the value of p? Give your answer in cm.
(a)
Length of the square
= 12 ÷ 4
= 3 cm
Total lengths of HJ, JK and KL
= 3 x 3
= 9 cm
Perimeter of triangle HLM
= 7
p + 12 - 3 - 3
= (7
p + 6) cm
(b)
7
p + 12 = 68
7
p = 68 - 12
7
p = 56
p = 56 ÷ 7 = 8
Value of
p = 8 cm
Answer(s): (a) (7
p + 6) cm; (b) 8 cm