PSLE The perimeter of figure EFGHJ is (7
f + 21) cm. The perimeter of square EFGH is 20 cm.
- Find the perimeter of triangle EHJ in terms of f.
- The perimeter of figure EFGHJ is 63 cm. What is the value of f? Give your answer in cm.
(a)
Length of the square
= 20 ÷ 4
= 5 cm
Total lengths of EF, FG and GH
= 3 x 5
= 15 cm
Perimeter of triangle EHJ
= 7
f + 21 - 5 - 5
= (7
f + 11) cm
(b)
7
f + 21 = 63
7
f = 63 - 21
7
f = 42
f = 42 ÷ 7 = 6
Value of
f = 6 cm
Answer(s): (a) (7
f + 11) cm; (b) 6 cm