PSLE The perimeter of figure TUVWX is (6
r + 23) cm. The perimeter of square TUVW is 20 cm.
- Find the perimeter of triangle TWX in terms of r.
- The perimeter of figure TUVWX is 59 cm. What is the value of r? Give your answer in cm.
(a)
Length of the square
= 20 ÷ 4
= 5 cm
Total lengths of TU, UV and VW
= 3 x 5
= 15 cm
Perimeter of triangle TWX
= 6
r + 23 - 5 - 5
= (6
r + 13) cm
(b)
6
r + 23 = 59
6
r = 59 - 23
6
r = 36
r = 36 ÷ 6 = 6
Value of
r = 6 cm
Answer(s): (a) (6
r + 13) cm; (b) 6 cm