PSLE The perimeter of figure JKLMN is (7
n + 17) cm. The perimeter of square JKLM is 8 cm.
- Find the perimeter of triangle JMN in terms of n.
- The perimeter of figure JKLMN is 66 cm. What is the value of n? Give your answer in cm.
(a)
Length of the square
= 8 ÷ 4
= 2 cm
Total lengths of JK, KL and LM
= 3 x 2
= 6 cm
Perimeter of triangle JMN
= 7
n + 17 - 2 - 2
= (7
n + 13) cm
(b)
7
n + 17 = 66
7
n = 66 - 17
7
n = 49
n = 49 ÷ 7 = 7
Value of
n = 7 cm
Answer(s): (a) (7
n + 13) cm; (b) 7 cm