PSLE The perimeter of figure JKLMN is (6
x + 22) cm. The perimeter of square JKLM is 16 cm.
- Find the perimeter of triangle JMN in terms of x.
- The perimeter of figure JKLMN is 58 cm. What is the value of x? Give your answer in cm.
(a)
Length of the square
= 16 ÷ 4
= 4 cm
Total lengths of JK, KL and LM
= 3 x 4
= 12 cm
Perimeter of triangle JMN
= 6
x + 22 - 4 - 4
= (6
x + 14) cm
(b)
6
x + 22 = 58
6
x = 58 - 22
6
x = 36
x = 36 ÷ 6 = 6
Value of
x = 6 cm
Answer(s): (a) (6
x + 14) cm; (b) 6 cm