PSLE The perimeter of figure JKLMN is (7
p + 25) cm. The perimeter of square JKLM is 8 cm.
- Find the perimeter of triangle JMN in terms of p.
- The perimeter of figure JKLMN is 88 cm. What is the value of p? Give your answer in cm.
(a)
Length of the square
= 8 ÷ 4
= 2 cm
Total lengths of JK, KL and LM
= 3 x 2
= 6 cm
Perimeter of triangle JMN
= 7
p + 25 - 2 - 2
= (7
p + 21) cm
(b)
7
p + 25 = 88
7
p = 88 - 25
7
p = 63
p = 63 ÷ 7 = 9
Value of
p = 9 cm
Answer(s): (a) (7
p + 21) cm; (b) 9 cm