PSLE The perimeter of figure HJKLM is (8
w + 22) cm. The perimeter of square HJKL is 24 cm.
- Find the perimeter of triangle HLM in terms of w.
- The perimeter of figure HJKLM is 94 cm. What is the value of w? Give your answer in cm.
(a)
Length of the square
= 24 ÷ 4
= 6 cm
Total lengths of HJ, JK and KL
= 3 x 6
= 18 cm
Perimeter of triangle HLM
= 8
w + 22 - 6 - 6
= (8
w + 10) cm
(b)
8
w + 22 = 94
8
w = 94 - 22
8
w = 72
w = 72 ÷ 8 = 9
Value of
w = 9 cm
Answer(s): (a) (8
w + 10) cm; (b) 9 cm