PSLE The perimeter of figure EFGHJ is (5
d + 24) cm. The perimeter of square EFGH is 24 cm.
- Find the perimeter of triangle EHJ in terms of d.
- The perimeter of figure EFGHJ is 69 cm. What is the value of d? Give your answer in cm.
(a)
Length of the square
= 24 ÷ 4
= 6 cm
Total lengths of EF, FG and GH
= 3 x 6
= 18 cm
Perimeter of triangle EHJ
= 5
d + 24 - 6 - 6
= (5
d + 12) cm
(b)
5
d + 24 = 69
5
d = 69 - 24
5
d = 45
d = 45 ÷ 5 = 9
Value of
d = 9 cm
Answer(s): (a) (5
d + 12) cm; (b) 9 cm