PSLE The perimeter of figure JKLMN is (8
i + 11) cm. The perimeter of square JKLM is 8 cm.
- Find the perimeter of triangle JMN in terms of i.
- The perimeter of figure JKLMN is 35 cm. What is the value of i? Give your answer in cm.
(a)
Length of the square
= 8 ÷ 4
= 2 cm
Total lengths of JK, KL and LM
= 3 x 2
= 6 cm
Perimeter of triangle JMN
= 8
i + 11 - 2 - 2
= (8
i + 7) cm
(b)
8
i + 11 = 35
8
i = 35 - 11
8
i = 24
i = 24 ÷ 8 = 3
Value of
i = 3 cm
Answer(s): (a) (8
i + 7) cm; (b) 3 cm