PSLE The perimeter of figure VWXYZ is (8
k + 25) cm. The perimeter of square VWXY is 28 cm.
- Find the perimeter of triangle VYZ in terms of k.
- The perimeter of figure VWXYZ is 89 cm. What is the value of k? Give your answer in cm.
(a)
Length of the square
= 28 ÷ 4
= 7 cm
Total lengths of VW, WX and XY
= 3 x 7
= 21 cm
Perimeter of triangle VYZ
= 8
k + 25 - 7 - 7
= (8
k + 11) cm
(b)
8
k + 25 = 89
8
k = 89 - 25
8
k = 64
k = 64 ÷ 8 = 8
Value of
k = 8 cm
Answer(s): (a) (8
k + 11) cm; (b) 8 cm