PSLE The perimeter of figure HJKLM is (4
x + 12) cm. The perimeter of square HJKL is 8 cm.
- Find the perimeter of triangle HLM in terms of x.
- The perimeter of figure HJKLM is 48 cm. What is the value of x? Give your answer in cm.
(a)
Length of the square
= 8 ÷ 4
= 2 cm
Total lengths of HJ, JK and KL
= 3 x 2
= 6 cm
Perimeter of triangle HLM
= 4
x + 12 - 2 - 2
= (4
x + 8) cm
(b)
4
x + 12 = 48
4
x = 48 - 12
4
x = 36
x = 36 ÷ 4 = 9
Value of
x = 9 cm
Answer(s): (a) (4
x + 8) cm; (b) 9 cm