PSLE The perimeter of figure HJKLM is (5
h + 13) cm. The perimeter of square HJKL is 20 cm.
- Find the perimeter of triangle HLM in terms of h.
- The perimeter of figure HJKLM is 43 cm. What is the value of h? Give your answer in cm.
(a)
Length of the square
= 20 ÷ 4
= 5 cm
Total lengths of HJ, JK and KL
= 3 x 5
= 15 cm
Perimeter of triangle HLM
= 5
h + 13 - 5 - 5
= (5
h + 3) cm
(b)
5
h + 13 = 43
5
h = 43 - 13
5
h = 30
h = 30 ÷ 5 = 6
Value of
h = 6 cm
Answer(s): (a) (5
h + 3) cm; (b) 6 cm