PSLE The perimeter of figure TUVWX is (7
s + 21) cm. The perimeter of square TUVW is 12 cm.
- Find the perimeter of triangle TWX in terms of s.
- The perimeter of figure TUVWX is 77 cm. What is the value of s? Give your answer in cm.
(a)
Length of the square
= 12 ÷ 4
= 3 cm
Total lengths of TU, UV and VW
= 3 x 3
= 9 cm
Perimeter of triangle TWX
= 7
s + 21 - 3 - 3
= (7
s + 15) cm
(b)
7
s + 21 = 77
7
s = 77 - 21
7
s = 56
s = 56 ÷ 7 = 8
Value of
s = 8 cm
Answer(s): (a) (7
s + 15) cm; (b) 8 cm