PSLE The perimeter of figure HJKLM is (4
q + 21) cm. The perimeter of square HJKL is 24 cm.
- Find the perimeter of triangle HLM in terms of q.
- The perimeter of figure HJKLM is 57 cm. What is the value of q? Give your answer in cm.
(a)
Length of the square
= 24 ÷ 4
= 6 cm
Total lengths of HJ, JK and KL
= 3 x 6
= 18 cm
Perimeter of triangle HLM
= 4
q + 21 - 6 - 6
= (4
q + 9) cm
(b)
4
q + 21 = 57
4
q = 57 - 21
4
q = 36
q = 36 ÷ 4 = 9
Value of
q = 9 cm
Answer(s): (a) (4
q + 9) cm; (b) 9 cm