PSLEJulian travelled 7.1 km in a taxi from the pool to the bistro. His taxi fare was based on the charges shown.
Taxi fare |
Charge |
First km |
$4.50 |
Every additional 300 m or less |
$0.54 |
How much was Julian's taxi fare?
1 km = 1000 m
7.1 km = 7.1 x 1000 = 7100 m
Distance charged as additional 300 m or less
= 7100 - 1000
= 6100 m
Number of sets of 300 m
= 6100 ÷ 300
= 20 r 100
Number of sets of 300 m to pay for
= 20 + 1
= 21
Julian's taxi fare
= 4.50 + (21 x 0.54)
= 4.50 + 11.34
= $15.84
Answer(s): $15.84