PSLEVincent travelled 5.8 km in a taxi from the farm to the cafe. His taxi fare was based on the charges shown.
Taxi fare |
Charge |
First km |
$2.60 |
Every additional 450 m or less |
$0.61 |
How much was Vincent's taxi fare?
1 km = 1000 m
5.8 km = 5.8 x 1000 = 5800 m
Distance charged as additional 450 m or less
= 5800 - 1000
= 4800 m
Number of sets of 450 m
= 4800 ÷ 450
= 10 r 300
Number of sets of 450 m to pay for
= 10 + 1
= 11
Vincent's taxi fare
= 2.60 + (11 x 0.61)
= 2.60 + 6.71
= $9.31
Answer(s): $9.31