PSLEDaniel travelled 5.2 km in a taxi from the bistro to the mall. His taxi fare was based on the charges shown.
Taxi fare |
Charge |
First km |
$2.50 |
Every additional 250 m or less |
$0.62 |
How much was Daniel's taxi fare?
1 km = 1000 m
5.2 km = 5.2 x 1000 = 5200 m
Distance charged as additional 250 m or less
= 5200 - 1000
= 4200 m
Number of sets of 250 m
= 4200 ÷ 250
= 16 r 200
Number of sets of 250 m to pay for
= 16 + 1
= 17
Daniel's taxi fare
= 2.50 + (17 x 0.62)
= 2.50 + 10.54
= $13.04
Answer(s): $13.04