PSLEJustin travelled 4.5 km in a taxi from the hotel to the school. His taxi fare was based on the charges shown.
Taxi fare |
Charge |
First km |
$3.50 |
Every additional 200 m or less |
$0.47 |
How much was Justin's taxi fare?
1 km = 1000 m
4.5 km = 4.5 x 1000 = 4500 m
Distance charged as additional 200 m or less
= 4500 - 1000
= 3500 m
Number of sets of 200 m
= 3500 ÷ 200
= 17 r 100
Number of sets of 200 m to pay for
= 17 + 1
= 18
Justin's taxi fare
= 3.50 + (18 x 0.47)
= 3.50 + 8.46
= $11.96
Answer(s): $11.96