PSLEDaniel travelled 6.6 km in a taxi from the store to the park. His taxi fare was based on the charges shown.
Taxi fare |
Charge |
First km |
$2.20 |
Every additional 300 m or less |
$0.64 |
How much was Daniel's taxi fare?
1 km = 1000 m
6.6 km = 6.6 x 1000 = 6600 m
Distance charged as additional 300 m or less
= 6600 - 1000
= 5600 m
Number of sets of 300 m
= 5600 ÷ 300
= 18 r 200
Number of sets of 300 m to pay for
= 18 + 1
= 19
Daniel's taxi fare
= 2.20 + (19 x 0.64)
= 2.20 + 12.16
= $14.36
Answer(s): $14.36