PSLEWesley travelled 5.5 km in a taxi from the store to the hotel. His taxi fare was based on the charges shown.
Taxi fare |
Charge |
First km |
$3.30 |
Every additional 400 m or less |
$0.57 |
How much was Wesley's taxi fare?
1 km = 1000 m
5.5 km = 5.5 x 1000 = 5500 m
Distance charged as additional 400 m or less
= 5500 - 1000
= 4500 m
Number of sets of 400 m
= 4500 ÷ 400
= 11 r 100
Number of sets of 400 m to pay for
= 11 + 1
= 12
Wesley's taxi fare
= 3.30 + (12 x 0.57)
= 3.30 + 6.84
= $10.14
Answer(s): $10.14