PSLEVaidev travelled 5.5 km in a taxi from the pool to the store. His taxi fare was based on the charges shown.
Taxi fare |
Charge |
First km |
$2.90 |
Every additional 200 m or less |
$0.52 |
How much was Vaidev's taxi fare?
1 km = 1000 m
5.5 km = 5.5 x 1000 = 5500 m
Distance charged as additional 200 m or less
= 5500 - 1000
= 4500 m
Number of sets of 200 m
= 4500 ÷ 200
= 22 r 100
Number of sets of 200 m to pay for
= 22 + 1
= 23
Vaidev's taxi fare
= 2.90 + (23 x 0.52)
= 2.90 + 11.96
= $14.86
Answer(s): $14.86