PSLE Usha took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 3 minutes and travelled a total distance of 4.9 km to reach Usha's home. How much was her taxi fare?
Taxi Fare |
|
First km |
$2.20 |
Every additional 500 m or less |
$0.29 |
Every 30 seconds waiting or less |
$0.30 |
Amount to pay for the first 1 km = $2.20
Remaining distance to pay for
= 4.9 - 1
= 3.9 km
1 km = 1000 m
3.9 km = 3.9 x 1000 = 3900 m
Sets of additional 500 m
= 3900 ÷ 500
= 7 r 400
Sets of additional 500 m or less
= 7 + 1
= 8
Amount to pay for remaining 3.9 km
= 8 x 0.29
= $2.32
1 min = 60 s
3 min = 3 x 60 = 180 s
Sets of 30 seconds of waiting
= 180 ÷ 30
= 6 r 0
Amount to pay for sets of 30 seconds of waiting or less
= 6 x 0.30
= $1.80
Usha's taxi fare
= 2.20 + 2.32 + 1.80
= $6.32
Answer(s): $6.32