PSLE Min took a taxi from her office to her home. Her taxi fare was based on the charges shown. The taxi stopped once at a traffic light for 2 minutes and travelled a total distance of 5.8 km to reach Min's home. How much was her taxi fare?
Taxi Fare |
|
First km |
$2.60 |
Every additional 400 m or less |
$0.43 |
Every 45 seconds waiting or less |
$0.30 |
Amount to pay for the first 1 km = $2.60
Remaining distance to pay for
= 5.8 - 1
= 4.8 km
1 km = 1000 m
4.8 km = 4.8 x 1000 = 4800 m
Sets of additional 400 m
= 4800 ÷ 400
= 12 r 0
Amount to pay for remaining 4.8 km
= 12 x 0.43
= $5.16
1 min = 60 s
2 min = 2 x 60 = 120 s
Sets of 45 seconds of waiting
= 120 ÷ 45
= 2 r 30
Sets of 45 seconds of waiting or less
= 2 + 1
= 3
Amount to pay for sets of 45 seconds of waiting or less
= 3 x 0.30
= $0.90
Min's taxi fare
= 2.60 + 5.16 + 0.90
= $8.66
Answer(s): $8.66